Completed
[Calculus] Sect 7.4 #7, Integral of x^4/(x-1), Partial Fraction, Stewart Calc 7th ET ed
Class Central Classrooms beta
YouTube videos curated by Class Central.
Classroom Contents
Calculus - Partial Fractions - Stewart Calculus Solution, 7th ET Edition
Automatically move to the next video in the Classroom when playback concludes
- 1 [Calculus] Sect 7.4 #7, Integral of x^4/(x-1), Partial Fraction, Stewart Calc 7th ET ed
- 2 Q63, FAST WAY TO DO PARTIAL FRACTION FOR INTEGRALS
- 3 the cover-up method & why it works! (for partial fractions decomposition)
- 4 This is how we partial fraction, repeated linear factors, "build up the power"
- 5 This is how we partial fraction, repeated linear roots, "cover-up method"
- 6 build up power for partial fractions? (design your own integrals#2)
- 7 [Calculus] Sect 7.4 #9, Integral of (5x+1)/((2x+1)(x-1)), Partial Fraction, Stewart Calc 7th ET ed
- 8 Why cover-up method for partial fraction works? sect 7.4 #9
- 9 Sect 7.4 #19, Partial Fraction with repeated linear factor
- 10 Sect 7.4 #19, Partial Fraction with Cover Up
- 11 [Calculus] Sect 7.4 #19, Partial Fraction, Stewart Calc 7th ET ed
- 12 [Calculus] Sect 7.4 #21, Integral of (x^3+4)/(x^2+4), Partial Fraction, Stewart Calc 7th ET ed
- 13 integral of 1/(x^2+a^2)
- 14 Partial Fraction 10/((x-1)(x^2+9))
- 15 [Calculus] Sect 7.4 #23, Integral of 10/((x-1)(x^2+9)), Partial Fraction, Stewart Calc 7th ET ed
- 16 Integral of x/(x^2+9)
- 17 integration with completing the square, Sect 7.4 #29
- 18 Q68, integral of 1/(x^3+x),
- 19 partial fraction for 1/(x(x^2+1))
- 20 Substitution first, then partial fractions, integral of 1/(sqrt(x)+cube root of x)
- 21 Q62, Integral by completing the square, and u sub, calculus 2
